The graph of y = ax^2 + bx + c is shown below. Find a times b times c. (The distance between the grid lines is one unit.)
Note the vertex at 3, 8
vertex form y = a(x-3)^2 + 8 sub in a point to solve for 'a' I'll use 5,4
4 = a ( 5-3)^2 + 8
a = -1
y = -(x-3)^2 + 8 expand to y = -x^2 + 6x -1 <======== take it from here !