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The graph of y = ax^2 + bx + c is shown below. Find a times b times c. (The distance between the grid lines is one unit.)

 

 Feb 1, 2022
 #1
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Note the vertex at    3, 8

 

  vertex form       y = a(x-3)^2 + 8     sub in a point to solve for 'a'      I'll use 5,4

                           4 = a ( 5-3)^2 + 8

                             a = -1

 

y = -(x-3)^2 + 8      expand to  y =    -x^2 + 6x -1      <======== take it from here !

 Feb 1, 2022

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