The graph of f(x) = (2x)/(3x^2 - 6x - 14) has vertical asymptotes x = a and x = b, and horizontal asymptote y = c. Find a + b + c.
Find a + b + c.
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\(3x^2 - 6x - 14=0\ |\ /3\\ x^2-2x-\frac{14}{3}=0\\ x=1\pm \sqrt{1+\frac{14}{3}}\)
\(a=-1.380\\ b=3.380\)
\(c=0\ \color{black}(graphic) \)
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