Assume that $f(3) = 4$. Name a point that must be on the graph of $y= 1/5*f(5x + 5) - 5$.
i am confused this problem..
thank you!
5x + 5 = 3
5x = -2
x = -2/5
So
(1/5) f( 5x + 5) - 5 =
(1/5)f(5 (-2/5) + 5) - 5 =
(1/5) f(3) - 5 =
(1/5) (4) - 5 =
-21/5
The point is (-2/5, - 21/5)