The mass of the Earth is 5.972×1024 kg
Its radius is 6.371×106 m
Calculate the intensity of gravity on the Earth.
HINT: $$g=\frac{m \cdot G}{r^2}$$
g stands for gravity
m stands for mass
G is a constant and is equal to 6.67×10-11 N•m2•kg-2
r stands for the radius
$$\boxed{ g=\dfrac{m \cdot G}{r^2} }$$
$$\\\small{\text{$g_{earth}=G*\dfrac{m_{earth}}{r_{earth}^2}\qquad G= 6.673 * 10^{-11} * \frac { N*\ m^2 } { kg^2 } \qquad m_{earth}=5.972\cdot 10^{24}\ kg\qquad r_{earth}=6.371\cdot 10^6\ m$}}\\\\
\small{\text{$g_{earth}=6.673 \cdot 10^{-11}*\dfrac{ 5.972\cdot 10^{24} }{ ( 6.371\cdot 10^6 )^2}\cdot \frac{N\cdot \ m^2 \cdot\ kg}{ kg^2\cdot\ m^2 } = \dfrac{ 6.673\cdot 5.972\cdot 10^{-11+24-12}} { 6.371^2 } \cdot \frac { N } { kg } $}}\\\\
\small{\text{$g_{earth}= \dfrac{ 6.673\cdot 5.972\cdot 10^{1}} { 6.371^2 } \cdot \frac { \dfrac{kg\cdot \ m }{s^2} } { kg } $}}\\\\
\small{\text{$g_{earth}= 9.81806072145\cdot \dfrac{ m }{s^2}$}}$$
Can Heureka have smaller cookie next time please. That one choked up my computer and it gave Heureka a belly ache
SO
The gravitational force between two objects is $$F=\frac{Gm_1m_2}{r^2}$$
but
If you want the intensity of gravity for the Earth it is just $$g=\frac{Gm_E}{r^2}$$
That actually does make sense I think :/
Sorry, that was the smallest cookie I had under the hand I'll try to find a smaller one.