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# h(t)=(t+3)^2+5

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h(t)=(t+3)^2+5

Over which interval does h have a negative average rate of change?

(Choice A)

A

1 \leq t \leq 41≤t≤41, is less than or equal to, t, is less than or equal to, 4

(Choice B, Checked)

B

-3 \leq t \leq 4−3≤t≤4minus, 3, is less than or equal to, t, is less than or equal to, 4

(Choice C)

C

-2 \leq t \leq 0−2≤t≤0minus, 2, is less than or equal to, t, is less than or equal to, 0

(Choice D)

D

-4 \leq t \leq -3−4≤t≤−3

Jul 13, 2021

#1
+121000
+1

This  is  a parabola  that  turns  upward.......the  vertex  is  (-3, 5)

h  will have  a  negative  rate  of   change  on the time interval  (-inf, -3)

See the graph here  :   https://www.desmos.com/calculator/cmdoy1jrdp

(x  = t  , and    y =  h )

Jul 13, 2021