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h[(tan-1(7.10/-3.52))]

 Aug 13, 2015

Best Answer 

 #1
avatar+118723 
+5

h[(tan-1(7.10/-3.52))]

 

$$\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{tan}}^{\!\!\mathtt{-1}}{\left({\frac{{\mathtt{7.1}}}{-{\mathtt{3.52}}}}\right)} = -{\mathtt{63.628\: \!951\: \!849\: \!611^{\circ}}}$$

 

h[63.629°]     has no particular meaning to me    

 Aug 13, 2015
 #1
avatar+118723 
+5
Best Answer

h[(tan-1(7.10/-3.52))]

 

$$\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{tan}}^{\!\!\mathtt{-1}}{\left({\frac{{\mathtt{7.1}}}{-{\mathtt{3.52}}}}\right)} = -{\mathtt{63.628\: \!951\: \!849\: \!611^{\circ}}}$$

 

h[63.629°]     has no particular meaning to me    

Melody Aug 13, 2015

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