What is thex -coordinate of the point on thex -axis that is equidistant from pointsA(-2,0) and B(0,4)?
+36916 The point will be (x,0) because it is on the x-axis
distance from -2, 0 is (distance formula) (x - - 2)^2 = d^2
distance from 0,4 (x-0)^2 + ( 0-4^2) = d^2
The distances are equal
(x+2)^2 = x^2 + 16
x^2 + 4x + 4 = x^2 + 16
4x = 12
x = 3 the point is 3,0
