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What is thex -coordinate of the point on thex -axis that is equidistant from pointsA(-2,0)  and B(0,4)?

 Apr 23, 2020
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The point will be    (x,0) because it is on the x-axis

 

distance from  -2, 0      is  (distance formula)    (x - - 2)^2 = d^2

distance from   0,4                                             (x-0)^2 + ( 0-4^2) = d^2

 

The distances are equal

   (x+2)^2  = x^2 + 16

x^2 + 4x + 4 = x^2 + 16

4x = 12

x = 3                           the point is    3,0

 Apr 23, 2020

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