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Write an equation with solutions -1, 2, and 3.

 Feb 9, 2023
 #1
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+3

Using the factor theorem (This states that if \(r\) is a solution to \(f(x)=0\), then \((x-r)\) is a factor of \(f(x)\)), we have \(f(x)=(x+1)(x-2)(x-3)=x^3-4x^2+x+6\).

 Feb 10, 2023

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