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# halp plz!

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There is a box of chocolates and one person easts one-fourth of the pieces and another person eats one-half of the remaining pieces. If there are now six pieces left, then how many pieces were originally in the box?

Oct 16, 2020

#1
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This is a pretty simple question. We know for sure the number is most probably under 30. So you can guess in check. Such as this:

Number: 28

1/4 of 28 = 7

21 - 1/2 = 10.5

So it doesnt fit the equation, so it isn't number 29

Number: 18

1/4 of 18 = 4.5

1/2 of 14.5 = 7.25

So it doesnt fit the equation, so it isn't number 18. Since 7.25 is close to six it's probably around the range 12-17

Number: 12

1/4 of 12 = 3

1/2 of 9 = 4.5

So it doesnt fit the equation, so it isn't number 12. Since the number was under, and 18 was above, it probably is 14-17

Number: 14

1/4 of 14: 3.5

1/2 of 11.5: 5.75

So it doesnt fit the equation. So it isn't number 14. Since the number was under, and 18 was above, it is probably 17

Number: 17

1/4 of 17: 4.25

1/2 of 13.75

This is above, but if you can round, as this is a decimal, this can count. Now though you should try decimals like this:

16.1,16.2,16.3,16.4, but if you can round the answer is the number 17 READ MY EXPLANATION IK YOU PROBABLY WONT

Oct 16, 2020
#2
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Let the original number of chocolates in the box =C

C - 1/4C = 3/4C left

3/4C / 2 = 6 pieces left

3/8C = 6

C = 6 / (3/8) =6 x (8/3) =48 / 3 = 16 - Original number of chocolates in the box.

Oct 16, 2020