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# halp plz

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Given that $$f(x) = x^k$$ where $$k > 0$$, what is the range of $$f(x)$$ on the interval $$[1, \infty)$$?

I don't know how to solve this. I am not that good at functions.

I saw a previus answer, $$(0,1]$$ and it was wrong.

THX IN ADVANCE

Aug 17, 2019

### 2+0 Answers

#1
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$$\text{if k>0 and x>1 then x^k>x}\\ \text{if k>0 and x=1 then x^k=1}\\ \text{so the range of f(x) for x \in [1,\infty) is f(x) \in [1,\infty)}$$

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Aug 18, 2019
#2
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THX SO MUCH.

Aug 18, 2019