Given that \(f(x) = x^k\) where \(k > 0\), what is the range of \(f(x)\) on the interval \([1, \infty)\)?
I don't know how to solve this. I am not that good at functions.
I saw a previus answer, \((0,1]\) and it was wrong.
THX IN ADVANCE
\(\text{if $k>0$ and $x>1$ then $x^k>x$}\\ \text{if $k>0$ and $x=1$ then $x^k=1$}\\ \text{so the range of $f(x)$ for $x \in [1,\infty)$ is $f(x) \in [1,\infty)$}\)
THX SO MUCH.
