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avatar+291 

You have a machine that can add exactly 46,899 pieces of candy per scoop to a giant vat and another machine that can remove exactly 13,576 pieces of candy with a different scoop from the giant vat. You have a total supply of 600,000 pieces of candy. Your giant vat starts out empty. The first machine adds scoops of candy, and then the second machine removes scoops of candy. When these two machines are done, there is only one piece of candy left in the vat. How many scoops of candy did the first machine add to the vat?

 Mar 22, 2019
 #1
avatar+2068 
+3

Well all you have to do is 

600,000 divided by 46,899 = 12.7934497537260922

The answer is from thew calculator so 

it might be 12.7

or just stick with 12.7934497537260922

 Mar 22, 2019
 #2
avatar+291 
+1

That is the wrong answer.

 Mar 23, 2019
 #3
avatar+2068 
+3

Wait What 

Nickolas  Mar 23, 2019
 #4
avatar+2068 
+3

EVEN if how do you know are you just teasting people????

Nickolas  Mar 23, 2019
 #5
avatar+291 
+1

Dude I asked my teacher she said no.

Badada  Mar 23, 2019
 #6
avatar+99659 
+2

We can use the Euclidian Algorithm to solve this

 

46899x + 13576y  = 1

46899  = (3)13576 + 6171

13576  = (2) 6171 + 1234

6171 = (5) 1234 + 1

 

1   =  6171 - (5) 1234

1 = 6171 -  5 [ 13576 - (2) 6171 ]

1 = (11) 6171 - (5) 13576

1 = (11) [ 46899 - (3)13576 ] - (5)13756

1 = 46899 (11) - 13576(38)

 

The first machne added

 

46899 (11)  = 515889  pieces of candy to the vat 

 

 

 

cool cool cool

 Mar 23, 2019
 #7
avatar+291 
+1

Dang that is still not the correct answer 

Badada  Mar 23, 2019
 #8
avatar+100247 
+2

Do you know what the correct answer is?  

If you do you should share it with us.  

Melody  Mar 23, 2019
 #9
avatar+100247 
+2

I get the same as Chris

One machine added  11 scoops      the other machine took 38 scoops

 Mar 23, 2019
 #10
avatar+291 
+1

Ok it is 11 i misunderstood CPhill

 Mar 24, 2019

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