You have a machine that can add exactly 46,899 pieces of candy per scoop to a giant vat and another machine that can remove exactly 13,576 pieces of candy with a different scoop from the giant vat. You have a total supply of 600,000 pieces of candy. Your giant vat starts out empty. The first machine adds scoops of candy, and then the second machine removes scoops of candy. When these two machines are done, there is only one piece of candy left in the vat. How many scoops of candy did the first machine add to the vat?

Badada Mar 22, 2019

#1**+3 **

Well all you have to do is

600,000 divided by 46,899 = 12.7934497537260922

The answer is from thew calculator so

it might be 12.7

or just stick with 12.7934497537260922

Nickolas Mar 22, 2019

#6**+2 **

We can use the Euclidian Algorithm to solve this

46899x + 13576y = 1

46899 = (3)13576 + 6171

13576 = (2) 6171 + 1234

6171 = (5) 1234 + 1

1 = 6171 - (5) 1234

1 = 6171 - 5 [ 13576 - (2) 6171 ]

1 = (11) 6171 - (5) 13576

1 = (11) [ 46899 - (3)13576 ] - (5)13756

1 = 46899 (11) - 13576(38)

The first machne added

46899 (11) = 515889 pieces of candy to the vat

CPhill Mar 23, 2019