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Find constants A, B, C, and D such that \( \frac{4x^3 - 20x^2 + 37x -25}{(x-2)^3(x-1)} = \frac{A}{x - 1} + \frac{B}{(x -2)^3} + \frac{C}{(x-2)^2}+\frac{D}{x-2}. \)Enter the order quadruple \((A, B, C, D).\)

 May 19, 2020
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PLZ HURRY

 May 19, 2020

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