Halp!

thanks for the help!

I am really confused about this one, I thought the answer was 15 but that is wrong

So

even * odd = even

odd*odd = odd

even*even.= even

even+odd = odd

even+even = even

odd + odd = even

So for subsets containing 2 we must have 2 odds.Thus all odds work.

6odds-

6c2 = 15

Trios: We must have all odds, but odd+odd+ odd = odd.so thus there are no possibilities for subsets with odd amounts.

quadruplets:

Again, odd oddd odd odd

6c4, again we have 15

6-lets

1 choice, 6c6

Thus 15+15+1 = 31

Not sure if correct, but I think it its.

First off, the awnswer is NOT 31(I did it). And this person is a current participant in the MBMT Online Math Tournament. It is against the rules to use the internet to find solutions.