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A square is inscribed in a circle of radius 5 centimeters. What is the value of \(x^2+y^2\) 

Guest Aug 17, 2017

Best Answer 

 #1
avatar+17745 
+1

The opposite vertices of a square are the endpoints of a diameter of that square.

Therefore, the angle between the x- and y-sides of the square is a right angle and x and y are the sides of a right triangle.

Since the radius of the circle is 5, its diameter is 10:

x2 + y = 102.

geno3141  Aug 17, 2017
 #1
avatar+17745 
+1
Best Answer

The opposite vertices of a square are the endpoints of a diameter of that square.

Therefore, the angle between the x- and y-sides of the square is a right angle and x and y are the sides of a right triangle.

Since the radius of the circle is 5, its diameter is 10:

x2 + y = 102.

geno3141  Aug 17, 2017

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