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+1
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avatar+194 

If y=x^2-7 and x is a real number, then what is the minimum value possible for y?

 Apr 12, 2021
 #1
avatar+104 
+3

can y be nagative?

 Apr 12, 2021
 #2
avatar+104 
+3

if it could then x = 1 and 1 - 7 = -6

if not then x = 3 and 9 - 7 = 2

 Apr 12, 2021
 #3
avatar+118626 
+1

y  =  x^2  - 7

 

The  minimum  value  of  x^2  =  0

 

So

 

y  =  0  -  7   =   - 7   = the minimum  value  of  y

 

 

cool cool cool

 Apr 12, 2021
 #4
avatar+194 
+1

Thanks!

 Apr 12, 2021
 #5
avatar+118626 
0

Welcome  !!!!

 

 

cool cool cool

CPhill  Apr 12, 2021

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