The triangle shown is a right triangle. The semicircles have the sides of the triangle as diameters. The areas of two of the semicircles are shown. What is the area of the third semicircle?
+324 If we use the pythagorean theorem, then the diameter of the last side is √(49+169) = √218
R=√(54.5)
A=54.5π
Ans= (54.5π)/2 = 27.25π
The triangle shown is a right triangle. The semicircles have the sides of the triangle as diameters. The areas of two of the semicircles are shown. What is the area of the third semicircle?
1/ {sqrt[(7 * 2) / pi]} * 2 = 4.222008246 ( short leg )
2/ {sqrt[(13 * 2) / pi]} * 2 = 5.753627392 ( long leg )
3/ {[sqrt(4.2220082462 + 5.7536273922)] / 2}2 *pi / 2 = 20 u2 ( area of largest semicircle ) 
