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Find the number of real solutions to \[(x^{2006} + 1)(x^{2004} + x^{2002} + x^{2000} + \dots + x^2 + 1) = 2006x^{2005}.\]

 Jan 16, 2021
 #1
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By Descartes Rule of Signs, there are three real soutions.

 Jan 16, 2021
 #2
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I really don't want to be mean, but this is the standard format of a purpose wrong answer from a guest, anybody that sees this:

"by the some rule, this is the answer"

do not enter the answer

 Jan 16, 2021

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