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Find the area of triangle ABC, given that AH=11 and HD=5

 Mar 24, 2024
 #1
avatar+128399 
+1

Triangle FBC   similar to  triangle DBA

DB / DA  = FB / FC

DB / 16 = FB / FC

 

Triangle FBC  similar to triangle DHC

FB / FC  = DH / DC

FB/FC  = 5 / DC

 

DB  / 16 = 5 / DC

80  = DB * DC

80  = DB * DB

80  = DB^2

DB = 4sqrt (5)

 

[ ABC  ] =   DB * DA  = 4sqrt (5) * 16  =   64sqrt (5)

 

CORRECTED

 

cool  cool  cool

 Mar 24, 2024
edited by CPhill  Mar 26, 2024
 #2
avatar+70 
0

that is unfortantly incorrect

faiafronk  Mar 24, 2024
 #3
avatar+70 
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around 80=DB*2DB, how did you get 2DB because you already have a DB at the start?

if we just did 80=DB^2, then we would have gotten the right answer. 

Thanks for the explanation!

faiafronk  Mar 25, 2024
 #4
avatar+128399 
0

Sorry....see my corrected answer  !!!!

 

cool cool cool

CPhill  Mar 26, 2024

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