halp!

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+70

Find the area of triangle ABC, given that AH=11 and HD=5

faiafronk Mar 24, 2024

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4⁺⁰ Answers

+129881

+1

Triangle FBC similar to triangle DBA

DB / DA = FB / FC

DB / 16 = FB / FC

Triangle FBC similar to triangle DHC

FB / FC = DH / DC

FB/FC = 5 / DC

DB / 16 = 5 / DC

80 = DB * DC

80 = DB * DB

80 = DB^2

DB = 4sqrt (5)

[ ABC ] = DB * DA = 4sqrt (5) * 16 = 64sqrt (5)

CORRECTED

CPhill Mar 24, 2024

edited by CPhill Mar 26, 2024

+70

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that is unfortantly incorrect

faiafronk Mar 24, 2024

+70

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around 80=DB*2DB, how did you get 2DB because you already have a DB at the start?

if we just did 80=DB^2, then we would have gotten the right answer.

Thanks for the explanation!

faiafronk Mar 25, 2024

+129881

0

Sorry....see my corrected answer !!!!

CPhill Mar 26, 2024

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