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# Halp

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The line segment connecting $(-2,7)$ and $(3,11)$ can be parameterized by the equations

\begin{align*}
x &= at + b, \\
y &= ct + d,
\end{align*}

where $0 \le t \le 1,$ and $t = 0$ corresponds to the point $(-2,7).$ Find $a^2 + b^2 + c^2 + d^2.$

Jan 6, 2022

### 1+0 Answers

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The parametric equations are x = 3t - 2 and y = 5t + 7, so a^2 + b^2 + c^2 + d^2 = 3^2 +(-2)^2 + 5^2 + 7^2 = 87.

Jan 6, 2022