halp!

I'm  not  exactly sure  what you  mean  by  n  copies, but I think it might be this...if  we  apply  alternating signs  to  each  digit  - generating a sum of the digits -  and  this  sum  is either  0  or  divisible by 11, then  the  number  is  divisible by 11

So

If  we  repeat   2020    8  times   and append    1  at  the end

We get

2020  2020  2020  2020  2020  2020   2020  2020 1

If we begin  with a plus sign on the first digit, all  the digits  will  be positive  and their sum =  33   which is divisible by 11

Note  :   202020202020202020202020202020201/11   =  18365472910927456382001836547291

So   n  =   8

i've done this one, u did it correct!