The function $f$ satisfies \[f(\sqrt{x + 1}) = \frac{1}{x}\]for all $x \ge -1,$ $x\neq 0.$ Find $f(2)$.
\(\text{The function f satisfies }f(\sqrt{x+1})=\frac{1}{x} \text{ for all }x\ge-1, x\neq0. \text{ Find f(2).}\)
When x is 3 then sqrt(3+1) = 2, so f(2) = 1/3.
