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In the diagram, square $ABCD$ has sides of length 4, and $\triangle ABE$ is equilateral. Line segments $BE$ and $AC$ intersect at $P$. Point $Q$ is on $BC$ so that $PQ$ is perpendicular to $BC$ and $PQ=x$. Find the value of $x$ in simplest radical form.

 Oct 20, 2019
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x = 6*sqrt(2) - 8.

 Nov 27, 2019

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