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Let \(f(x)=\frac{(x-2)^2-9}{3}\).

The equation y=f(x) is graphed, and the x and y intercepts of the graph are connected to form a polygon. What is the area of that polygon?

 Jul 27, 2020
 #1
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The area of the polygon is 13/3.

 Jul 27, 2020
 #2
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Thank you for atempting the problem, but I am trying to learn, just an answer is not enough.

 

Also I double checked and 13/3 is not the correct answer to this problem.

 

Can someone else please atempt this problem?

Guest Jul 27, 2020
 #3
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 I can post my solution, though I do not know if is correct....   I got   area = 32/3 ??

 Jul 28, 2020
 #4
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I'm sorry but I checked and 32/3 is not correct.

The hint under the solution says that it is an integer

Guest Jul 29, 2020
 #5
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A good start would be to graph the function and draw the polygon:

 

The polygon is clearly a triangle, the area of which is given by (1/2)base*height.  The base length is fairly obvious. To get the height, simply find f(0).

 Jul 29, 2020
edited by Alan  Jul 29, 2020
edited by Alan  Jul 29, 2020

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