Solve for $n$ in the equation $\frac{2-n}{n+1} + \frac{2n-4}{2-n} = 7$.
answer is -(7/10).
\frac{2-n}{n+1} + \frac{2n-4}{2-n} = 7
\Rightarrow \frac{2-n}{n+1} + \frac{-2(2-n)}{2-n} =7
\Rightarrow \frac{2-n}{n+1} -2 =7
\Rightarrow \frac{2-n}{n+1} =9
\Rightarrow 2-n =9n+9
\Rightarrow 10n=-7
\Rightarrow n=-(7/10)
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