ABCD is a right trapezium with AB parallel to CD and ∠BAD=∠ADC=90∘. The diagonals AC and BD intersect at E. If AB=7, DC = 28 and AD = 75AD=75, what is the area of triangle BEC?
ABCD is a right trapezium with AB parallel to CD and ∠BAD=∠ADC=90∘. The diagonals AC and BD intersect at E. If AB=7, DC = 28, and AD = 75, what is the area of triangle BEC?
Area of a triangle BEC = 210 units squared.
1) Calculate angles DAC and DBM ( ∠DAC = ∠MNC = ∠ENB ) ( ∠DBM = ∠EBN )
2) Find line segments MN and BN
3) Find the area of a triangle BNC
4) Find the area of a triangle BEN using the law of sines and Heron's formula.
Add these two areas ( BNC and BEN ) and you're done.
( Btw, the above post is mine too)