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avatar+9673 

Simplify the expressions. Round off to 3 significant figures if necessary. Give the answer in scientific notation.

2. (f)

\(\sqrt[3]{1.25\times10^{200}}\)

 

This is one of the questions of the Law of Indices quiz which I have taken today. No one in the class could do this :( . Thought I would get full marks again :(

(P.S. :I get full marks in nearly every quizes, but not tests)

(P.P.S. : I nearly got full marks in my last yearly exam. Ended up with a score 91 out of 94.)

 Sep 14, 2016
edited by MaxWong  Sep 14, 2016

Best Answer 

 #1
avatar+33661 
+10

Hint: 

 

5^3 = 125

 

(10^66)^3 = 10^198

.

 Sep 14, 2016
 #1
avatar+33661 
+10
Best Answer

Hint: 

 

5^3 = 125

 

(10^66)^3 = 10^198

.

Alan Sep 14, 2016
 #2
avatar+118673 
+5

Come on Max, cant you work it out from Alan's answer - or do you need more help??

 

I thought Alan's answer was a good one :))

 

If you need more help just say so :))

 Sep 14, 2016
 #3
avatar+9673 
+5

Is it 5 x 10^66?

MaxWong  Sep 14, 2016
 #4
avatar+118673 
+5

\sqrt[3]{1.25\times10^{200}}

 

\(\sqrt[3]{1.25\times10^{200}}\\ =\sqrt[3]{1.25}\times\sqrt[3]{10^{200}}\\ =\frac{\sqrt[3]{125}}{\sqrt[3]{100}}\times\sqrt[3]{10^{198}}*\sqrt[3]{100}\qquad \text{I have used Alan's hit here}\\ =\frac{\sqrt[3]{125}}{1}\times\sqrt[3]{10^{198}}*1\\ =5\times 10^{66}\\\)

 

So yes your answer is correct :)

Melody  Sep 14, 2016
 #5
avatar
+5

Come on MaxWong, a very smart young man like you couldn't figure this one out!!? I just don't believe it:

 

[1.25 x 10^200]^1/3 =[125 x 10^198]^1/3 =5 x 10^66

 Sep 14, 2016
 #6
avatar+9673 
0

young man??

More like a teenager :)

PS: I am 14 years old.

MaxWong  Sep 16, 2016

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