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Let a and b be positive real numbers such that a+b=1. Find the set of all possible values of 1a+1b.

 May 13, 2024
 #1
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1a+1b=a+bab=1ab

 

Since a and b are positive real numbers, ab>0. Consequently, 1ab>0.

 

Then, 1a+1b(0,).

 May 13, 2024

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