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Let  and  be nonzero complex numbers such that 

a = (b+c)/(x-2)

b = (c+a)/(y-2)

c = (a+b)/(z-2)
xy + yx + xz = 67

x + y + z = 2010
Find the value of xyz. 

 May 30, 2021
 #1
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xyz = 231.

 May 30, 2021

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