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avatar+533 

Let \(f(x)=x^2+6x+1\), and let \(R\) denote the set of points \((x,y)\) in the coordinate plane such that \(f(x) + f(y) \leq 0 \)and \(f(x)-f(y)\leq0\).

 

The area of \(R\) rounded to the nearest whole number is....

 Jan 28, 2019
edited by asdf335  Mar 24, 2019
 #1
avatar+4789 
+1

You know how to do it but you want to see if anyone else does?

 

So when no one bothers with it you can bask in the illusion of your supremacy?

 

Here's an idea... p i s s off.

 Jan 28, 2019
 #2
avatar+533 
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ok then, idc about you, as long as you keep your bullying ways to urself, LOL!

asdf335  Jan 29, 2019
 #4
avatar+100103 
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Asad,

Rom was not trying to bully you. 

He was responding in anger to what he saw as rudeness from you.

 

I thought what you wrote was rude too but I do not think you intended to be rude.

However, no matter what degree of intent you had, your post was rude.

It was understandable for Rom to respond the way he did.

 

Now accept Rom's response as a lesson and learn from it !

Melody  Jan 29, 2019
edited by Melody  Jan 29, 2019
edited by Melody  Jan 29, 2019
 #3
avatar+86 
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LMFAO!! I knew it! I knew it!

We have another Troll. And this one can do math at least as well as Nauseated.

There’s now a triple sprite dynamic on the forum. A Chimp, A Gorilla, and a ??? 

What kind of Troll is Rom?   Whatever. We have a quorum!

 Jan 29, 2019
 #5
avatar+7477 
+1

This looks like a fun problem. I will try later, perhaps tomorrow if I remember laugh.

 Jan 29, 2019
 #6
avatar+7477 
+1

And here I am, attempting the problem :P

I used a graphing calculator, looked at the graph and then found the area of R xD

 

That's half of a circle with radius 4 units, which is \(\dfrac{\pi\cdot4^2}{2} = 8\pi\).

 

I can't find a proper way of doing this. 

MaxWong  Jan 30, 2019

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