FE and FG are tangents to circle J. Find JE.
Tangents drawn to a circle from the same point are equal in length......therefore.....
FE = FG
2(3 + 6x) = 14x - 8
6 + 12x = 14x - 8
6 + 8 = 14x - 12x
14 = 2x
14 / 2 = x = 7
So
JE = 4 (7) = 28
