A rescuer on a helicopter is 80ft above the sea drops a lifebelt.The distance from the lifebelt to the sea can be modeled by the equation h(t)= -16t²+s, where t is the time, in seconds, after the lifebelt is dropped, and s is the initial height, in feet, of the lifebelt above the sea.How long will it take for the lifebelt to reach the sea? Round your answer to the nearest tenth of a second.
+36916 s = 80 given
when the belt hits the sea h(t) = 0
0 = -16t^2 + 80 solve for t
t^2 = 80/16 = 5
t = sqrt 5 =~~ 2.2 seconds
