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The figure shown has a parallelogram on top and a rectangle below it:

A figure has a rectangular portion, and above the rectangle there is a parallelogram. The length of the rectangle is 48.2 inches, the width of the rectangle is 7.3 inches, and the height of the parallelogram is 13.4 inches.

What is the total area of the figure?

 Mar 22, 2019
 #1
avatar+1014 
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Could someone show me the steps of how to do this

 Mar 22, 2019
 #2
avatar+475 
-1

To calculate the area of this figure we need to know the area of the parrallogram and rectangle the shapes are clearly outlined so we don't need to worry on which thing to find...... 

 

The formula to find the area of a parallogram is.

 

\(Area = Base*Height\)

 

The Formula of a rectangle is. 

 

\(Area = length * With\) 

 

 

Then we work out are problem and calculate the following   

 

 

Using the formula for the rectangle we look at the length of the each sides we never want to calcualte to SIDES or LINES THAT ARE PARALLEL in a rectangle

 

and by looking at the rectangle we can see it has a  

 

With of 7.3 inches  

Length of 48.2   

 

Now we multiply them together and are product will be the area of the rectangle. 

 

\(7.3 * 48.2 = 351.86\) 

So this mean are current value and the are of the rectangle is 351.86 Sq inches  

 

Now all we have to do is find the area of the parallogram which I find similar to finding the area of a rectangle 

 

We see that the parrallogram has an exact base as the rectangle and has a height of 13.4 Sq inches so we multiply them together 

 

\(48.2 * 13.4 = 645.88\)

 

So now we know the parralogram's area is equal to 645.88 sq inches so now all we have to do is add are area's and find our answer. 

 

\(351.86 + 645.88 = 997.74\)

 

so we now know are toal area is 997.74 Sq inches.

 Mar 22, 2019
edited by HiylinLink  Mar 22, 2019
 #3
avatar+1014 
-2

Thanks Now I get it.

Nickolas  Mar 22, 2019

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