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$${{\mathtt{x}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{4}}{\mathtt{\,\times\,}}{\mathtt{x}} = -{\mathtt{1}}$$

 Mar 26, 2015

Best Answer 

 #2
avatar+118609 
+5

$$\\x^2+4x=-1\\
x^2+4x+1=0\\$$

Use the quadratic formula :)

 

$${{\mathtt{x}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{4}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}} = {\mathtt{0}} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = {\mathtt{\,-\,}}{\sqrt{{\mathtt{3}}}}{\mathtt{\,-\,}}{\mathtt{2}}\\
{\mathtt{x}} = {\sqrt{{\mathtt{3}}}}{\mathtt{\,-\,}}{\mathtt{2}}\\
\end{array} \right\} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = -{\mathtt{3.732\: \!050\: \!807\: \!568\: \!877\: \!3}}\\
{\mathtt{x}} = -{\mathtt{0.267\: \!949\: \!192\: \!431\: \!122\: \!7}}\\
\end{array} \right\}$$

.
 Mar 27, 2015
 #1
avatar+10 
0

add four on both sides 

 Mar 26, 2015
 #2
avatar+118609 
+5
Best Answer

$$\\x^2+4x=-1\\
x^2+4x+1=0\\$$

Use the quadratic formula :)

 

$${{\mathtt{x}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{4}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}} = {\mathtt{0}} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = {\mathtt{\,-\,}}{\sqrt{{\mathtt{3}}}}{\mathtt{\,-\,}}{\mathtt{2}}\\
{\mathtt{x}} = {\sqrt{{\mathtt{3}}}}{\mathtt{\,-\,}}{\mathtt{2}}\\
\end{array} \right\} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = -{\mathtt{3.732\: \!050\: \!807\: \!568\: \!877\: \!3}}\\
{\mathtt{x}} = -{\mathtt{0.267\: \!949\: \!192\: \!431\: \!122\: \!7}}\\
\end{array} \right\}$$

Melody Mar 27, 2015

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