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In △ABC, D lies on BC⎯⎯⎯⎯⎯⎯⎯⎯ such that BD=32CD. If AB=2AC and AD=32CD, what is the value of cos∠ADC (enter answer in fraction form)?

 

 

 

 

2017_Image_HS_Bracket_IV_Question_7.jpg

 Mar 17, 2020
 #1
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workin' on it.....

 Mar 17, 2020
 #2
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In △ABC, D lies on BC⎯⎯⎯⎯⎯⎯⎯⎯ such that BD=32CD. If AB=2AC and AD=32CD, what is the value of cos∠ADC (enter answer in fraction form)?

 

AB = 62.225

AD = BD = 32

CD = 1

AC = 31.1125

∠DAB = ∠DBA = 13.523277°

∠ADC = 27.046554°

cos∠ADC = 0.89063735   ≈  89 / 100  indecision 

Dragan  Mar 18, 2020
edited by Dragan  Mar 18, 2020

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