In △ABC, D lies on BC⎯⎯⎯⎯⎯⎯⎯⎯ such that BD=32CD. If AB=2AC and AD=32CD, what is the value of cos∠ADC (enter answer in fraction form)?
2017_Image_HS_Bracket_IV_Question_7.jpg
workin' on it.....
AB = 62.225
AD = BD = 32
CD = 1
AC = 31.1125
∠DAB = ∠DBA = 13.523277°
∠ADC = 27.046554°
cos∠ADC = 0.89063735 ≈ 89 / 100
