In triangle XYZ, \angleY = 45^\circ and \angleZ = 60^\circ. If XZ = 4, then what is XY?
By the Sine Law, XY = 3 - sqrt(3).
We have that
XY/ sin Z = XZ / sin Y
XY/ sin 60° = 4 / sin 45°
XY = 4sin 60° /sin 45°
XY = 4 sqrt (3) / sqrt (2)
XY = 4 sqrt (6) / 2 = 2sqrt (6)
XY / XZ = sin(∠X) / sin(∠Y)
XY = 2√6
