Find the area of the region enclosed by the graph of x^2 + y^2 = 2x - 6y + 6.
Completing the square, we get (x - 2)^2 + (y + 6)^2 = 28, so the area of the circle is 28*pi.
That is incorrrect.
x2 + y2 = 2x -6y + 6
x2 -2x + y2 + 6y = 6
x2 -2x + 4 + y2 + 6y + 9 = 6 + 4 + 9
(x - 2)2 + (y + 3)2 = 19
Eqn of a circle with radius2 = 19
The answer is 16pi.
