Find the vertex of the graph of the equation....
1. \(x - y^2 + 8y = 13\)
2. \(y = -2x^2 + 8x - 15\)
Arrange first one as x = y^2 -8y+13 then the 'y' value of the vertex will be found (this is a sideways parabola)
as - b/2a where b = - 8 a =1 use THIS value in the equation to find the 'x' value
y = -2x^2 + 8x -15 vertex 'x' value will be -b/2a b = 8 a = -2 use THIS value in the equation to find the vertex 'y' value
So what's the answer?
It's not my homework. It's a bet, with a friend who is smart, (unlike me).
Could you please give me a full solution?