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Find the vertex of the graph of the equation....

 

1. \(x - y^2 + 8y = 13\)

2. \(y = -2x^2 + 8x - 15\)

 Jun 30, 2020
 #1
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Arrange first one as    x = y^2 -8y+13           then the 'y' value of the vertex will be found   (this is a sideways parabola)

                                                                  as   - b/2a     where b = - 8  a =1     use THIS value in the equation to find the 'x' value

 

 

y = -2x^2 + 8x -15        vertex 'x' value will  be   -b/2a   b = 8     a = -2      use THIS value in the equation to find the vertex 'y' value

 Jun 30, 2020
edited by ElectricPavlov  Jun 30, 2020
 #2
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So what's the answer?

 Jun 30, 2020
 #3
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Beats me ....   What did YOU find after I told you HOW to get the answer?   I'm not here to puke up answers to people's homework cheeky

ElectricPavlov  Jun 30, 2020
 #9
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I really need the answer!  Can't you just give me the answer?

Guest Jun 30, 2020
 #5
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It's not my homework. It's a bet, with a friend who is smart, (unlike me).

 

Could you please give me a full solution?

 Jun 30, 2020
 #6
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For a full solution, EP will need to chase a half-pint of Magnesia Milk with Ipecac, because he will have to shit while puking up the answer.  

Guest Jun 30, 2020
 #7
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LMFAO!!

Guest Jun 30, 2020
 #8
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Unhelpful.

 Jun 30, 2020
 #10
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Anybody?

 Jul 1, 2020
 #11
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First one: (-3,4)

Second: (2,-7)

 Jul 1, 2020

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