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\((((\sqrt[n]{n}^{\sqrt[n]{n}})^{\sqrt[n]{n}})^{\displaystyle\overbrace\cdots^{n+1 \; times}})^{\sqrt[n]{n}}\)=?
Total n+1 times of \sqrt[n]{n} power.....

 Sep 4, 2016

Best Answer 

 #1
avatar+9665 
+5

Is it n? ;)

Let the original expression = y

y = \(\sqrt[n]{n}^{\overbrace{\sqrt[n]{n}\times\cdots \sqrt[n]{n}}^{\text{ n times}}}=\sqrt[n]{n}^n=n\)

 Sep 4, 2016
 #1
avatar+9665 
+5
Best Answer

Is it n? ;)

Let the original expression = y

y = \(\sqrt[n]{n}^{\overbrace{\sqrt[n]{n}\times\cdots \sqrt[n]{n}}^{\text{ n times}}}=\sqrt[n]{n}^n=n\)

MaxWong Sep 4, 2016
 #2
avatar+12531 
+5

It is n.

 Sep 4, 2016

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