+0  
 
0
495
1
avatar

viewing angle 41.8 x 80' + 5'5"=

 Oct 19, 2016
 #1
avatar+26388 
0

viewing angle 41.8 x 80' + 5'5"= ?

 

\(\begin{array}{|rcll|} \hline && 41.8 \times 80' + 5'5" \\ &=& 41.8 \times 80' + 5' + 5" \\ &= & 41.8 \times 80' + 5'+ 5"\cdot \frac{1'}{60"} \\ &= & 41.8 \times 80' + 5'+ \left(\frac{5}{60} \right)' \\ &= & 3344' + 5'+ \left(\frac{5}{60} \right)' \\ &= & 3349' + \left(\frac{5}{60} \right)' \\ &= & 3349'\cdot \frac{60}{60} + \left(\frac{5}{60} \right)' \\ &= & \frac{3349' \cdot 60+5'}{60} \\ &= & \frac{200945'}{60} \cdot \frac{ 1^{\circ} }{60'}\\ &= & \left(\frac{200945}{60\cdot 60} \right)^{\circ}\\ &=& 55.8180\bar5 ^{\circ} \\ \hline \end{array}\)

 

laugh

 Oct 20, 2016

3 Online Users

avatar
avatar
avatar