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A pontoon with base 3 m by 3 m is floating on a lake. When a man swims out and climbs onto it the pontoon
sinks 1 cm. If 1 L of water weighs 1 kg, what is the weight of the man? (Hint: Archimedes’ principle tells us
that the weight of the man is equal to the weight of water displaced.)

 May 21, 2020

4+0 Answers

 #1
avatar+14923 
+1

What is the weight of the man?

 

Hello Guest!

 

\(3m\times 3m\times 1cm\times \frac{1kg}{dm^3}\times\frac{100dm^2}{m^2}\times\frac{dm}{10cm}=\color{blue}90kg\)

The weight of the man is 90kg.

 

laugh  !

.
 May 21, 2020
edited by asinus  May 21, 2020
 #3
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0

why is there the dm^3?

Guest May 21, 2020
 #4
avatar+14923 
+1

\(Mass = volume\ times\ density.\)

\(The\ density\ of\ water\ is\ \frac{1kg}{dm^3}.\)

laugh  !

asinus  May 22, 2020
edited by asinus  May 22, 2020
edited by asinus  May 22, 2020
 #2
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0

how tho?

 May 21, 2020

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