From the top of a vertical cliff that is 40 m high, a ship is spotted at an angle of depression of 25 degrees. How far from the base of the cliff is the ship , to the nearest metre ?
+37093 The observer , the cliff base and the ship form a right triangle ...we are looking for the second leg of the triangle given 40 is the first leg
the 40 is opposite of the 25 degree angle ....
Tan 25 = 40/x
x = 40/tan25 =~ 86 m (to the mearest m)
