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Consider the ellipse \[\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1,\]where $a > b.$ As a function of $a$ and $b,$ find the radius of the smallest circle that contains the ellipse, is centered on the $y$-axis, and which intersects the ellipse only at $(0,b).$

 Feb 27, 2021
 #1
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From the tangency condition, the smallest radius is 2a.

 Feb 27, 2021
 #2
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I didn't even put it in, because I didn't show the form of the answer, it has to be a fraction, may this be a an attention, when a guest gives an explanation that is reasonable you may use the answer, like these, 

 

the standard form

 

Usinf the: [Theory], this is the [Answer]

i have reposted this 3 times and the guests have used the same format and got three incorrect answers

 Feb 27, 2021

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