Hello!
How do you find the answer to: (b^2-2ab+a^2) / 2(a-b)
The answer is: (a-b) / 2
When I do it though I keep getting 1 as the answer:
(b^2-2ab+a^2) / 2(a-b) = (a-b)^2 / 2(a-b) = (a-b)^2 / (a-b)^2 = 1
What am I doing wrong?
Thanks in advance!
+37146 2 (a-b) does not equal (a-b)^2 is your wrong turn
(b^2-2ab+a^2) / 2(a-b) =
(b-a)^2 / (2(a-b) =
(b-a)^2 /(-2(b-a)) =
(b-a) / -2 =
(a-b)/2
1/2 (a-b)
