What is the domain of the real-valued function $$q(x) = \frac{\sqrt{x}}{\sqrt{1-x^2}}~?$$Express your answer as an interval or as a union of intervals.
\(q(x) = \frac{\sqrt{x}}{\sqrt{1-x^2}}\)
Note that.....for the function in the numerator, the domain is [ 0, ∞ )
For the function inthe denominator, the domain is (-1, 1)
But....we must use the most restrictive domain possible.....this is [ 0, 1 )
Here is a graph that will confirm this :
https://www.desmos.com/calculator/ywedl27com