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If \(abc = 13\) and

\(\left(a+\frac{1}{b}\right)\left(b+\frac{1}{c}\right)\left(c+\frac{1}{a}\right)=\left(1+\frac{1}{a}\right)\left(1+\frac{1}{b}\right)\left(1+\frac{1}{c}\right),\)

find \(a+b+c\)

 Jun 21, 2020
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a + b + c = 3*13 = 39.

 Jun 21, 2020

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