+0

# HELLPPPP

0
37
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Evaluate $(a^b)^a - (b^a)^b$ for $a = 2$ and $b = 3$.

Jul 2, 2021

#1
0

Substitute both numbers in ===> (2^3)^2 - (3^2)^3 = 2^6 - 3^6 = -665

Jul 2, 2021
#2
+320
+3

Hey there, Guest!

So, the equation is $$\left(a^b\right)^a-\left(b^a\right)^b\$$ and we'll substitute properly.

$$\left(2^3\right)^2-\left(3^2\right)^3$$

$$8^2−(3^2)^3$$

$$64−(3^2)^3$$

$$64−9^3$$

$$64−729$$

−665

Hope this helped! :)

( ﾟдﾟ)つ Bye

Jul 2, 2021
#3
+20
+1

This equals (2^3)^2 - (3^2)^3 = 2^6 - 3^6 = 64 - 729 = -665.

Jul 2, 2021