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A line segment beginning point A(-2,5) and ending at B(6,-7) is drawn on a coordinate plane. Point C(0,2) is plotted on AB. What is the ratio of AC to BC?

 Nov 16, 2015
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A line segment beginning point A(-2,5) and ending at B(6,-7) is drawn on a coordinate plane. Point C(0,2) is plotted on AB. What is the ratio of AC to BC?

 

Distance from A to C = sqrt[ (-2 -0)^2 + (5 - 2)^2]  = sqrt [ 4 + 9]  = sqrt(13)

Distance from B to C  = sqrt[ (6 - 0)^2 + ( -7 - 2)^2]   = sqrt [ 36 + 81]  = sqrt (117)

 

So  the ratio of AB to BC  = sqrt 13) / sqrt(117)   =  sqrt(13 / 117)   = sqrt( 1/9)   = 1/3

 

 

 

cool cool cool

 Nov 16, 2015

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