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Help 10,11

 May 16, 2018
 #1
avatar+429 
+2

10. https://www.desmos.com/calculator/ldobo0y17u

 

smileysmileysmiley

 May 16, 2018
 #2
avatar+101228 
+1

11.

 

The points of discontinuity  will be where the denominator   =  0

 

So...we want to  solve this

 

x^2 +  5x   - 6   =   0

 

factor

 

( x + 6) ( x -1)   = 0

 

Setting each factor to 0  and solving for  x  produces

 

x + 6  = 0            x  - 1   =  0

 

x  = -6                x  =  1    ⇒  third answer

 

 

cool cool cool

 May 17, 2018

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