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What is the area of Figure ABCD?

A trapezoid ABCD is drawn with length of parallel sides AB and CD equal to 14 inches and 18 inches, respectively. The length of one of the non-parallel sides BC is 7 inches. Side BC is perpendicular to DC. A perpendicular line drawn from A to side CD meets CD at E.

 Mar 24, 2019
 #1
avatar+533 
+2

Here's my work: https://snag.gy/SgLJCu.jpg

(It's my own writing with a mouse, so it's not pretty. :))

 Mar 24, 2019
 #2
avatar+1264 
+3

I am sorry but he will not be able to see it on here he has parental controls 

 but I will complelte this since I am here any way 

 

 

We have two shapes, A triangle and a rectangle. 

 

and the formula for the area's is 

 

Triangle \(Base * height * \frac{1}{2} = area\) 

 

Rectangle \(Length * With = area\) 

 

The first shape the rectangle has a length of 7 inches and with of 14 inches 

 

So lets first do the rectangle \(7 * 14 = 98 \) 

 

This means the area of the rectangle is 98 square inches. 

 

Now for the triangle the base is 4 inches and the height is 7 inches and using the formula above we will find the area  

\(4 * 7 * \frac{1}{2} = 14\)

 

So this means the area of the triangle is 14 square inches 

 

Now we add the products (Since we have been using multiplication) so 

 

\(98 + 14 = 102\)

 

So are answer is 102 Square inches 

 

(I hope you are grasping the concept we are teaching you have had alot of similar posts......)

HiylinLink  Mar 24, 2019
edited by HiylinLink  Mar 25, 2019
edited by HiylinLink  Mar 25, 2019
 #3
avatar+2068 
+4

Thanks asdf

 

I seen it Awsome 

 

and thanks Higylink 

Nickolas  Mar 25, 2019
 #4
avatar+2068 
+5

Thankyou for you help

Nickolas  Mar 25, 2019

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