a)
If we suppose that c varies inversely with d, then this is what that statement is telling you:
The most basic example of this occurence is \(y=\frac{1}{x}\). As you think of larger values of x, the input, then the output, y, will decrease.
There is only one difference from the previous function to this particular problem: We do not know the rate in which the inverse relation occurs. For example, if the numerator of the previous function was a 2, then the rate of the inverse function would double. Let's name the rate of the inverse relation "k." We, therefore, make the following equation.
\(c=\frac{k}{d}\)
b)
We can use the previous equation to figure out the rest. It involves basic substitution.
\(c=\frac{k}{d}\) | Substitute in the known values for c and d. |
\(17=\frac{k}{2}\) | Solve for k by multiplying by 2 on both sides. |
\(k=34\) | |
Now, let's find d when c=68:
\(c=\frac{k}{d}\) | We now know the values of c and k are this time. |
\(68=\frac{34}{d}\) | Now it is a matter of simplifying. |
\(68d=34\) | |
\(d=\frac{34}{68}=\frac{1}{2}=0.5\) | |
a)
If we suppose that c varies inversely with d, then this is what that statement is telling you:
The most basic example of this occurence is \(y=\frac{1}{x}\). As you think of larger values of x, the input, then the output, y, will decrease.
There is only one difference from the previous function to this particular problem: We do not know the rate in which the inverse relation occurs. For example, if the numerator of the previous function was a 2, then the rate of the inverse function would double. Let's name the rate of the inverse relation "k." We, therefore, make the following equation.
\(c=\frac{k}{d}\)
b)
We can use the previous equation to figure out the rest. It involves basic substitution.
\(c=\frac{k}{d}\) | Substitute in the known values for c and d. |
\(17=\frac{k}{2}\) | Solve for k by multiplying by 2 on both sides. |
\(k=34\) | |
Now, let's find d when c=68:
\(c=\frac{k}{d}\) | We now know the values of c and k are this time. |
\(68=\frac{34}{d}\) | Now it is a matter of simplifying. |
\(68d=34\) | |
\(d=\frac{34}{68}=\frac{1}{2}=0.5\) | |